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a6a06adb69
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a6a06adb69 | |||
adad0973f9 |
@ -12,8 +12,6 @@ This blew my mind, how counter-intuitive the answer to this question actually is
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This program runs 16 simulations where you start with a balance of 100 currencies. You make consecutive bets, always betting 80% of your total balance with a 70% chance of winning each bet. It then reports the results after ONLY 200 bets. The result is the percentage of your returns (your end balance divided by your starting balance).
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In other words, given enough time, we're all screwed.
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### Output
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Notice the e-n at the end... these are very small numbers, with only one simulation winning out with 24441% return based on the original balance.
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@ -35,6 +33,8 @@ Notice the e-n at the end... these are very small numbers, with only one simulat
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* 7.788708234095218e-09
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* 0.0041392388926358116
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In other words, given enough time, we're all screwed.
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### Reference Video
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[](https://www.youtube.com/watch?v=91IOwS0gf3g)
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23
main.go
23
main.go
@ -7,37 +7,46 @@ import (
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)
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func main() {
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// Random seed based on time when program runs
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rand.Seed(time.Now().UTC().UnixNano())
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var balance, investedPercentage, winningPercentage float64
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balance = 100
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// Initialize variables
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var startingBalance, investedPercentage, winningPercentage float64
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startingBalance = 100
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investedPercentage = 0.80
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winningPercentage = 0.70
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discreteCompoundingPeriods := 200
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numSimulations := 16
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outputChannel := make(chan float64)
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// Start simulations
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for i := 0; i < numSimulations; i++ {
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go simulation(balance, investedPercentage, winningPercentage, discreteCompoundingPeriods, outputChannel)
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go simulation(startingBalance, investedPercentage, winningPercentage, discreteCompoundingPeriods, outputChannel)
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}
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// Wait for simulations to finish and write output
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for i := 0; i < numSimulations; i++ {
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fmt.Println(<-outputChannel)
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}
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}
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// discrete period, symmetric payoff simulator
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func simulation(startingBalance, investedPercentage, winningPercentage float64, discreteCompoundingPeriods int, outputChannel chan float64) {
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balance := startingBalance
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// Each iteration is one bet
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for i := 0; i < discreteCompoundingPeriods; i++ {
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investedAmount := balance * investedPercentage
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// Each bet is a fixed percentage of the balance
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betAmount := balance * investedPercentage
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if rand.Float64() <= winningPercentage {
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// you win
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balance += investedAmount
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balance += betAmount
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} else {
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// you lose
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balance -= investedAmount
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balance -= betAmount
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}
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}
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// Calculate and report the result on the outputChannel
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outputChannel <- (balance / startingBalance)
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}
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